Question

Inside a car that was at STP, a 1.33 L bottle warms up to 130 C. If the volume of the bottle remains constant, what is the pressure, in atm, inside the hot water bottle?

Answer 1

`P_2=1.48atm`

Step-by-step explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to infer this problem is about the application of the Gay-Lussac's gas law to relate the initial and final pressure and temperature as shown below:

`(P_2)/(T_2) =(P_1)/(T_1\\ )`

Thus, solving for the final pressure, P2, and using the temperatures in Kelvins, we obtain:

`P_2 =(P_1T_2)/(T_1 )\\\\P_2 =(1atm*403.15K)/(273.15K)\\\\P_2=1.48atm`

Regards!