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4 Al (s) + 302(8) - 2Al2O3(s) How many grams of Al2O3 can be formed from 77.58 g of Al and 33.92 g of O2? (Hint: You need to determine which one is the limiting reactant).
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4 Al (s) + 302(8)

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2Al2O3(s)
How many grams of Al2O3 can be formed from 77.58 g of Al and 33.92 g of O2?
(Hint: You need to determine which one is the limiting reactant).

User Oskar Jensson Fjeld
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1 Answer

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Explanation 2Al2O3(s)-->4Al(s)+302(g)What is the total number of moles of O2 that are produced when 8.0 mol of Al2O3(s)are totally decomposed ?

User Chukwuma
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