Answer:
![(6x^3+40xy^2-45x^2y+30y^3)/(60)](https://img.qammunity.org/2022/formulas/mathematics/high-school/2272jpxe0f8seqsd6sc0kcmklay5nuim0c.png)
Explanation:
Primero que todo reescribiremos el problema como una ecuacion:
![(6)/(5)x^(3)-x^(3)+(4)/(3)xy^(2)-(3)/(2)x^(2) y+y^(3)](https://img.qammunity.org/2022/formulas/mathematics/high-school/jskyzf60mx1x8gd0uiomm3a0kd8sxxzwre.png)
Ahora rompemos el parentesis cambiando el signo:
![(3)/(5)x^(3)-(1)/(2)x^(3)+(2)/(3)xy^(2)-(3)/(4)x^(2) y+(1)/(2)y^(3)](https://img.qammunity.org/2022/formulas/mathematics/high-school/489dzh30f5q1c89r7ff0281knbe2ls4tjm.png)
Ahora simplificamos los terminos con variables iguales:
![(1)/(10)x^(3)+(2)/(3)xy^(2)-(3)/(4)x^(2) y+(1)/(2)y^(3)](https://img.qammunity.org/2022/formulas/mathematics/high-school/9c0rmvsg181qv3ds20mi7pu8py6mesmkx5.png)
Ahora restamos los primeros dos terminos y los ultimos dos terminos:
![(3x^(3)+20xy^(2))/(30)-(6x^2y+4y^3)/(8)](https://img.qammunity.org/2022/formulas/mathematics/high-school/krk67tdf2fne31qy3m46n1dvei8znpg5t6.png)
Y realizamos la ultima suma de fracciones:
![(24x^3+160xy^2-180x^2y+120y^3)/(240)](https://img.qammunity.org/2022/formulas/mathematics/high-school/5zpw45rf4nil4skztps2s3r3h1bzbc4mqk.png)
Y por ultimo podemos simplificar la espresion dividiento doto por 4:
![(6x^3+40xy^2-45x^2y+30y^3)/(60)](https://img.qammunity.org/2022/formulas/mathematics/high-school/2272jpxe0f8seqsd6sc0kcmklay5nuim0c.png)