Answer:
the x² test statistic 13.71
Option a) 13.71 is the correct answer.
Explanation:
Given the data in the question;
Feeder 1 2 3 4
Observed visits;
60 90 92 58
data sample = 300
Expected
= 300 / 4 = 75
the x² test statistic = ?
= ∑[ (
-
)²/
]
= [ (60 - 75)² / 75 ] + [ (90 - 75)² / 75 ] + [ (92 - 75)² / 75 ] + [ (58 - 75)² / 75 ]
= [ 3 ] + [ 3 ] + [ 3.8533 ] + [ 3.8533 ]
= 13.7066 ≈ 13.71
Therefore, the x² test statistic 13.71
Option a) 13.71 is the correct answer.