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A peanut was burned in a calorimeter filled with 70g of water. The temperature

increased from 21°C to 87°C. How much heat was released by the peanut. The
specific heat of water is 4.18 J/gºC *

1 Answer

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Answer:


heat = mc \triangle \theta \\ = 70 * 4.18 * (87 - 21) \\ = 19311.6 \: joules

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