Question

The half price of helium-5 is 7.6 X 10 to the power of negative 22 seconds and the half-life helium -9 is 7 x 10 to the power of negative 21-second approximately how many times greater is the half life of helium and -9 then that of helium -5

Answer 1

Approximately 9.211 times

Explanation:

Given

`x = 7.6 * 10^(-22)s` --- half life of helium-5

`y = 7 * 10^(-21)s` --- half life of helium-9

Required

How many times greater is y than x

To do this, we simply divide y by x

`(y)/(x) = (7 * 10^(-21)s)/(7.6 * 10^(-22)s)`

`(y)/(x) = (7 * 10^(-21))/(7.6 * 10^(-22))`

Apply law of indices

`(y)/(x) = (7 * 10^(-21--22))/(7.6)`

`(y)/(x) = (7 * 10^(-21+22))/(7.6)`

`(y)/(x) = (7 * 10)/(7.6)`

`(y)/(x) = (70)/(7.6)`

`(y)/(x) = 9.211`