Answer:
B.
![x^2+11x+24\leq 150](https://img.qammunity.org/2023/formulas/mathematics/high-school/yxc8hjqrrpg2t8xplqaextj89hcxewxz2c.png)
Explanation:
Step 1) Defining Sue and Jeremy's ages using x
Sue is 3 years older than Holly (h):
![h=x+3](https://img.qammunity.org/2023/formulas/mathematics/high-school/njr15vvxmwv0f4vlgr073xp1uddh9u7ptb.png)
Jeremy is 5 years older than Sue, or 8 years older than Holly (j):
![j=x+8](https://img.qammunity.org/2023/formulas/mathematics/high-school/hwki8o2oi0m3q8h6n035nl8fnrw96yo98o.png)
Product of Jeremy and Sue's ages is less than or equal to 150:
![hj\leq 150](https://img.qammunity.org/2023/formulas/mathematics/high-school/12a972xf0t32p36xhrhs66m3bodopz21vf.png)
Step 2) Simplifying into a single equation
Using the equation above we can substitute Sue and Jeremy's ages:
![(x+3)(x+8)\leq 150](https://img.qammunity.org/2023/formulas/mathematics/high-school/xyk18oxnc67tb7kcv6j2ngrtytw3gupb78.png)
Now we can simplify this equation. Use the distributive property first:
![x(x+8)=x^2+8x\\3(x+8)=3x+24](https://img.qammunity.org/2023/formulas/mathematics/high-school/t3fq33v2gm5eu5nd0zztbgr1xxfejy6an1.png)
Now add all the terms together and get the final answer:
![x^2+8x+3x+24\leq 150\\x^2+11x+24\leq 150](https://img.qammunity.org/2023/formulas/mathematics/high-school/m3woisol288vvza0xpvhb0xuf6o9bns3rw.png)
Final equation:
![x^2+11x+24\leq 150](https://img.qammunity.org/2023/formulas/mathematics/high-school/yxc8hjqrrpg2t8xplqaextj89hcxewxz2c.png)