Question

If 12.5 grams of Hydrogen and 5.14 grams of Oxygen react in a container what would be the excess leftovers? Thanks! :)

Answer 1

Step-by-step explanation:

2 H2 + 1 O2 => 2 H2O

molecular wt of H2 = 2

molecular wt of O2 = 32

so wt of H2 : wt of O2 = 2x2 : 16 = 4 : 16 = 1 : 4

there are way more H2 as 12.5 > 5.14/4 = 1.285

H2 leftovers = 12.5 - 1.285 = 11.215 gram

Answer 2

Step-by-step explanation:

The reaction is 2H2 + O2 -> 2 H2O

So the molar ratio of H2 and O2 is 2:1

No. of moles of H2 = 12.5/2 = 6.25

No. of moles of O2 = 5.14/32 =0.16

As 6.25 > 0.16*2 = 0.32

there will be H2 leftovers of 6.25-0.32 = 5.93 moles or 11.86 grams