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What is the slope of a line perpendicular to the line whose equation is x – 3y = 27.
Fully simplify your answer.

User Gill
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1 Answer

7 votes

Answer:

So a line perpendicular to this equation would be any line with a slope of -3/4 (the negative reciprocal of the slope)

Explanation:

First convert the original equation into y = form to find the slope.

Subtract 4x on both sides leaving -3y = -27 - 4x

This leaves y = (-27 - 4x)/(-3)

You can divide both -27 and -4x by -3 individually to get 9 and 4/3 respectively

This makes your equation y = 9 + (4/3)x

Whenever an equation is in y = mx + b form, the 'm' represents the slope. In this case the slope is 4/3.

User Jakuje
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