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Line JK passes through J(2,7) and K(5, 11).

What is the slope of line JK?



Helppp

1 Answer

7 votes

Answer: Slope is 4/3

Step-by-step explanation: slope is change of y / change of x

k = Δy/Δx = (7-11) /(2-5) = -4 / -3 = 4/3

User Nick Chubb
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