Question

One leg of a right triangle is 1 cm longer than the other leg. The hypotenuse measures 5 cm.

Part A: Find the perimeter of the triangle.

Part B: Find the area of a triangle

Answer 1

`hypotenuse = 5 \: cm \\ height = 5 - 1 = 4 \: cm \\ base = \sqrt{ {5}^(2) - {4}^(2) } = √(9) = 3 \: cm`

Part A:

`perimeter = 5 + 4 + 3 \\ = 12 \: cm`

Part B:

`area = (1)/(2) * base * height \\ = (1)/(2) * 3 * 4 \\ = 6 \: {cm}^(2)`