Question

G varies inversely with the square

of H. When H is 4, G is 0.25.
Find the value of G when H is 0.3.

Answer 1

Answer:;4.4

Step-by-step explanation: Since it varies inversely we know G times H squared is equal to some constant, k. So we have G*H*H=k. We are told that when H=4, G=.25. Plugging this in, we have .25*4*4=k. This simplifies to 4=k. Our new equation is G*H*H=4. Now, we want to solve for G when H=.3. We plug it in. G*.3*.3=4 => G*.09=4. G=4/.09. This means G is approximately 44.4.

Answer 2

G = 44.44

Explanation:

Given the mathematical expression and data;

`G = \frac {1}{H^(2)}`

H = 4 and G = 0.25

First of all, we would determine the constant of proportionality, k.

`G = \frac {k}{H^(2)}`

Making k the subject of formula, we have;

k = GH²

Substituting the values, we have;

k = 0.25 * 4²

k = 0.25 * 16

k = 4

Next, we find the value of G when H = 0.3;

`G = \frac {k}{H^(2)}`

`G = \frac {4}{0.3^(2)}`

`G = \frac {4}{0.09}`

G = 44.44