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What is the equation of the circle center (0, 3) and radius 4?

User Ayesh Don
by
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2 Answers

5 votes

Answer:

( x )² + ( y - 3 )² = 16

Explanation:

The general format for circular equations is ( x - a )² + ( y - b )² = r²

User Joslinm
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2 votes


\huge{ \mathfrak{  \underline{ Answer }\:  \:  ✓ }}

The equation of the circle is represented as :


\hookrightarrow (x - h) {}^(2) + (y - k) {}^(2) = (r) {}^(2)

where, h is x-coordinate and k is y-coordinate of center of the circle, and "r" is radius of the given circle.

Therefore, the equation of the above circle will look like :


\hookrightarrow(x - 0) {}^(2) + (y - 3) {}^(2) = {4}^(2)


\hookrightarrow {x}^(2) + (y - 3) {}^(2) = 16

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\mathrm{ ☠ \: TeeNForeveR \:☠ }

User Stesch
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