Question

2- Write aC+ program that calculates the sum of all even numbers from [1000,2000], using the while loop.

Answer 1

#include <iostream>

using namespace std;

int main() {

int n = 1000;

int sum = 0;

while(n <= 2000) {

sum += n;

n += 2;

}

cout << "sum of even numbers in [1000..2000] = " << sum << endl;

}

Step-by-step explanation:

This will output:

sum of even numbers in [1000..2000] = 751500