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Given f(x) = x2 + kx + 11, and the remainder when f(x) is divided by x + 1 is

21, then what is the value of k?

1 Answer

3 votes

Answer:


k=-9

Explanation:

According to the Polynomial Remainder Theorem, when dividing a polynomial P(x) by a binomial in the form (x - a), the remainder will be given by P(a).

We are given the polynomial:


f(x)=x^2+kx+11

And it is divided by the binomial:


x+1

The remainder is 21.

Rewriting the divisor yields:


x-(-1)

So, a = -1.

Then by the PRT:


f(-1)=(-1)^2+k(-1)+11=21

Simplify:


1-k+11=21

Solve for k:


k=-9

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