How many grams of aluminum is required to react with 75.0 ml of 2.50 M HCl?

asked Jun 20, 2022 139k views

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4 votes

Answer:

63 g Al is required to react with 35 mL of 2.50 M hydrochloric acid

I'm sorry if it's wrong, I tried.

Step-by-step explanation:

Paceaux answered Jun 26, 2022

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