90.4k views
2 votes
Machines J and K have the following investment and operating costs: Year 0 1 2 3 J 11000 1200 1300 K 13000 1200 1300 1400 Which machine is a better buy at a WACC of 10.5%

User ThrawnCA
by
8.9k points

1 Answer

2 votes

Answer:

Machine K

Step-by-step explanation:

The values can be better computed as:

Year 0 1 2 3

J 11000 1200 1`300

K 13000 1200 1300 1400

Using the PV Calculator

The Present Value (PV) for each year in Machine J is as follows:

Cashflow Year Present Value

11000 0 11000

1200 1 1085.97

1300 2 1064.68

Total 13,150.65

The effective annual cost =
(NPV* r)/(1-(1+r)^(-n))


=(13150.65 * 0.1050)/(1-(1+0.1050)^(-2))

= $7628.16

Using the PV Calculator

The Present Value (PV) for each year in Machine K is as follows:

Cashflow Year Present Value

13000 0 13000

1200 1 1085.97

1300 2 1064.68

1400 3 1037.63

Total 16,188.28

The effective annual cost =
(NPV* r)/(1-(1+r)^(-n))


=(16188.28 * 0.1050)/(1-(1+0.1050)^(-3))

= $6566.92

Therefore, machine K is better to buy than machine J.

User Myrdd
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories