Question

g A circular swimming pool has a diameter of 10 m, the sides are 4 m high, and the depth of the water is 3 m. How much work (in Joules) is required to pump all of the water over the side

Answer 1

`W=2.69*10^(6)J`

Step-by-step explanation:

Generally the equation for momentum is mathematically given by

Diameter
`d=10m`

Radius
`r =(d)/(2)=>5m`

Height
`h=4m`

Depth
`d=3m`

Generally the equation for Area of the circle is mathematically given by

`A=\pi r^2`

`A=\pi 5^2`

`A=78.5m^2`

Generally the equation for Work done is mathematically given by

`d_w=d_f*x`

Where

`d_f=(\rho*d_v)*g`

Therefore

`d_w=((\rho*d_v)*g)*x`

`d_w=((1000*78.5)*9.8)*x dx`

`d_w=769300x dx`

`W=\int dw`

`\int dw=769300 \int^4_(3)x dx`

`W=(769300\2)*7`

`W=2.69*10^(6)J`