Question

If 20.0 mLmL of a 0.100 NN acid solution is needed to reach the end point in titration of 32.5 mLmL of a base solution, what is the normality of the base solution

Answer 1

To find the normality of the base solution in a titration, use the formula: Normality of acid x Volume of acid = Normality of base x Volume of base.

Step-by-step explanation:

In a titration, the normality (N) of a solution is a measure of its concentration. To find the normality of the base solution, we can use the formula:

Normality of acid x Volume of acid = Normality of base x Volume of base

Plugging in the given values, we have:

0.100 N x 20.0 mL = Normality of base x 32.5 mL

Dividing both sides by 32.5 mL, we find that the normality of the base solution is 0.062 N.

Answer 2

The correct answer is "0.051 N".

Step-by-step explanation:

Given

Volume,

`V_1=20.0 \ mL`

`V_2=32.5 \ mL`

Normality,

`N_1=0.1 \ N`

`N_2=?`

As we know,

⇒
`N_1V_1=N_2V_2`

or,

⇒
`N_2=(N_1V_1)/(V_2)`

On putting the values, we get

⇒
`=(0.1* 20.0)/(32.5)`

⇒
`=(2)/(32.5)`

⇒
`=0.051 \ N`