Answer:
6.05 × 10⁴ cal
Step-by-step explanation:
Step 1: Given and required data
Mass of water (m): 112 g
Enthalpy of vaporization of water (ΔHvap): 540 cal/g
Step 2: Calculate how much energy is required to vaporize 112 g of water
Vaporization is a physical change in which a substance goes from the liquid state to the gaseous state. We can calculate the energy required (Q) using the following expression.
Q = ΔHvap × m
Q = 540 cal/g × 112 g = 6.05 × 10⁴ cal