Question

Using and spectrophotometer, you measure 2 dilutions of NADH, and get absorbance values of 0.4 for sample A, and 0.2 for sample B. You know that the path length is 1 cm, and the extinction coefficient for NADH is 6220 (L Morcm). Using the Lambert-Beer Law equation (below), calculate the concentrations of sample A Select] and Sample B (Select ] A = log10 () = Ecl Where: A- Absorbance C- Concentration (mol 1 - Path length (cm) E = molar decadic extinction coefficient L mol. cm 1o - Intensity of the incident light 1 - Intensity of the transmitted Night

Answer 1

The answer is "The concentration sample A= 0.00006
`(mol)/(L)` and concentration of sample B is 0.00003
`(mol)/(L)`".

Step-by-step explanation:

Length of path
`(l)=1 \ cm\\\\`

Coefficient extinction
`(\varepsilon )=6220\ (L)/(Mol \ cm)\\\\`

Absorbace of sample
`(A)=0.4\\\\`

Absorbace of sample
`(B)=0.2\\\\`

For sample A:

`A=\varepsilon cl\\\\0.4=6220 * c * 1\\\\c=(0.4)/(6220)\\\\`

`=0.00064\ (mol)/(L)`

For sample B:

`A=\varepsilon cl\\\\0.2=6220 * c * 1\\\\c=(0.2)/(6220)\\\\`

`=0.00003\ (mol)/(L)`