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Find the quotient of these complex numbers (6-I) divided by (4+3i)=

User Delvin
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1 Answer

4 votes

Answer:


(21)/(25) -(22)/(25) i

Explanation:

We can start by writing the division as a fraction:


(6-i)/(4+3i)

In order to rationalize the denominator, we need to multiply by the conjugate:


(6-i)/(4+3i) *(4-3i)/(4-3i)\\\\((6-i)(4-3i))/(4^2-(3i)^2)\\\\(24-18i-4i+3i^2)/(16+9)\\\\(24-22i-3)/(25)\\\\(21-22i)/(25) \\\\(21)/(25) -(22)/(25) i

User EFernandes
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