Question

Air in a thundercloud expands as it rises. If its initial temperature is 292 K and no energy is lost by thermal conduction on expansion, what is its temperature when the initial volume has tripled

Answer 1

Step-by-step explanation:

It is a case of adiabatic expansion .

`T_1V_1^(\gamma-1)=T_2V_2^(\gamma-1)`

T₁ , T₂ are initial and final temperature , V₁ and V₂ are initial and final volume.

Given ,

V₂ = 3 V₁ and T₁ = 292 . γ for air is 1.4 .

`( 3 )^(\gamma-1)= (292)/( T_2)`

`( 3 )^(1.4-1)= (292)/( T_2)`

1.552 = 292 / T₂

T₂ = 188 K .