Question

25.0 g of HCl is added to 100.0 g of water. The density of the resulting solution is 1.19 g/mL. Calculate the molality of

Answer 1

The molality is "6.86 m".

Step-by-step explanation:

Given:

Mass of of HCL,

= 25 g

Mass of water,

= 100 g

Density,

= 1.19 g/mL

Total mass of solution,

= 125 g

Now,

The number of moles of HCl will be:

=
`(25)/(36.458)`

=
`0.6857`

The solution volume will be:

=
`(125)/(1.19)`

=
`105.04 \ mL`

hence,

The molality will be:

=
`(No. \ of \ moles \ of \ solute)/(Mass \ of \ solvent (Kg))`

=
`(0.6857)/(0.1)`

=
`6.857 \ m`

or,

=
`6.86 \ m`