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The perimeter of a rectangle is 60 cm. The ratio of length to width is 3:2. Find the length and width of the rectangle.

User Kosnik
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Given :

  • The Perimeter of the rectangle is 60 cm
  • The ratio of the length to the width is 3:2.

To Find :

  • The Length and width of the rectangle .

Solution :

We know that,


\qquad{ \bold{ \pmb{2(Length + Breadth ) = Perimeter_((rectangle))}}}

Let's assume the length of the rectangle as 3x inches. and the width is 2x inches.

Now, Substituting the given values in the formula :


\qquad \dashrightarrow{ \sf{2(3x + 2x )= 60}}


\qquad \dashrightarrow{ \sf{2(6x)= 60}}


\qquad \dashrightarrow{ \sf{12x= 60}}


\qquad \dashrightarrow{ \sf{x= (60)/(12) }}


\qquad \dashrightarrow{ \bf{x= 5}}

Therefore,


\qquad { \pmb{ \bf{ Length _((rectangle)) = 3x \: = 3(5) = 15 \: inches}}}\:


\qquad { \pmb{ \bf{ Width _((rectangle)) = 2x = 2(5) = 10 \: inches}}}\:

User Gabriel West
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