Question

A parabola with the equation y=a(x-b)^2+c has a minimum of (-2,1) and a y-intercept of 5. What are the values of a, b and c? What are the x-intercepts?

Answer 1

Answer: 3^15

Step-by-step explanation: carry the one to the 5 divide by the third and multiply the fractions , find the mean ( average ) of the mode and square that to find your a b and c values