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If sin 0= 4/5 in quadrant II, what is cose? A. - 3/5 B. 3/5 C. - 3/4 D. 3/4

1 Answer

5 votes

Answer:

A

Explanation:

Given

sinθ =
(4)/(5) =
(opposite)/(hypotenuse)

This is a 3- 4- 5 triangle

with opposite = 4, adjacent = 3 and hypotenuse = 5

Since θ is in second quadrant then cosθ < 0

cosθ =
(adjacent)/(hypotenuse) = -
(3)/(5) → A

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