Question

Coherent monochromatic light falls perpendicularly on two slits (each of width 0.10 mm) separated by 0.50 mm. In the resulting interference pattern on a screen 2.80 m away, adjacent bright fringes are separated by 2.80 mm. (a)What is the wavelength of the light that falls on the slits

Answer 1

The correct answer is "
`0.5* 10^(-6) \ m`".

Step-by-step explanation:

Given:

`(\lambda D)/(d) =2.8* 10^(-3)`

`d = 0.5* 10^(-3)`

`D = 2.80`

Now,

The wavelength will be:

⇒
`\lambda = 2.8* 10^(-3)* (d)/(D)`

By putting the values, we get

⇒
`=(2.8* 10^(-3)* 0.5* 10^(-3))/(2.8)`

⇒
`=(1.4* 10^(-6))/(2.8)`

⇒
`=0.5* 10^(-6) \ m`