Question

The ship was travelling 93 meters per second, 25 degrees above the x-axis Northeast. Determine the magnitude and direction of the horizontal vector component, Vx.

Answer 1

Answer:
`92.18\ m/s`, east

Step-by-step explanation:

Given

Ship is traveling at a speed of
`v=93\ m/s`

Direction of ship is
`25^(\circ)` North of east

If we break velocity vector in x and y axes then, the horizontal component is given by

`\Rightarrow v_x=93\cos 25^(\circ)\\\Rightarrow v_x=92.18\ m/s`

The direction of horizontal component is towards east with magnitude of
`92.18\ m/s`