Question

How can I solve y^2 + 13y + 12?

Answer 1

`(y + 1)(y + 12)`

`\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}`

`{y}^(2) + 13y + 12 \\ = {y}^(2) + 12y + 1y + 12 \\ taking \: common \: factor \: from \: the \: two \: pairs \\ = y(y + 12) + 1(y + 12) \\ = (y + 1)(y + 12)`

`\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}`

Answer 2

(y+1)(y+12) that’s what I got.