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Given
Given 15 cot A = 8, find sin A and sec A.​

1 Answer

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Answer:


sin A = (15)/(17), \ sec A = \frac{17}8

Explanation:


15cot A = 8\\\\cotA = (8)/(15)\\\\1 + cot^2A = cosec^2 A\\\\1 + ((8)/(15))^2 = cosec^2 A\\\\1 + (64)/(225) = cosec^2A\\\\(225+64)/(225) = cosec^2 A\\\\cosec^2 A = (289)/(225)\\\\cosec A = (17)/(15)\\\\That \ is, \ (1)/(sin A) = (17)/(15)\\\\sin A = (15)/(17)


cot A = (8)/(15)\\\\(cos A)/(sinA) = (8)/(15)\\\\cos A = (8)/(15) * sin A = (8)/(15) * (15)/(17) = (8)/(17)\\\\(1)/(cosA) = (17)/(8)\\\\sec A = (17)/(8)

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