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6. Find the area of the segment. (the shaded region)

6. Find the area of the segment. (the shaded region)-example-1

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There are two pieces we need to find here: the area of the section of the circle, and the area of the triangle.

Area of the section of the circle:

A = pi * r^2

A = pi * 15^2

A = 225pi * 72/360 || We only need this part of the circle, not the whole thing.

A = 45pi

Area of the triangle:

A = 1/2 * a * b * sin(c)

A = 1/2 * 15 * 15 * sin(72)

A = 112.5 * sin(72)

Next, we need to subtract the area of the triangle from the area of the section of the circle.

A = 45pi - (112.5 * sin(72))

A = 112.8165 units^2 -- Feel free to round off wherever you need!

Hope this helps!! :)

User Puya Sarmidani
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