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A round asteroid has a surface gravity of 0.0288

If the mass of the asteroid is 1.10x10^18 kg, what is its radius??

User Zoombie
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4.5k points

2 Answers

7 votes

Answer:

50473.45

Step-by-step explanation:

(6.67×10^-11)(1.10×10^18)/(x)^2=0.0288.

User Uzay
by
4.4k points
2 votes

answer: 5.047345 × 10^4 (50473.45)

User TheShun
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4.4k points