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Solve for x. The triangles in each pair are similar. Please explain!! I’m so confused

Solve for x. The triangles in each pair are similar. Please explain!! I’m so confused-example-1

1 Answer

6 votes

Answer:


x = 5

Explanation:

Given


\triangle JDC similar to
\triangle JKL

Required

Find x

To do this, we make use of the following equivalent ratios


JK:JL = JD:JC

This gives


98 : 63 = 7x + 7:27

Express as fraction


(98 )/( 63) =( 7x + 7)/(27)

Multiply both sides by 27


27 * (98 )/( 63) =( 7x + 7)/(27) * 27


27 * (98 )/( 63) =7x + 7


3* (98 )/( 7) =7x + 7


3* 14 =7x + 7


42 =7x + 7

Collect like terms


7x = 42 - 7


7x = 35

Divide both sides by 7


x = 5

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