Question

Express the confidence interval (63.3%, 79.1%) in the form of ˆp ± ME.
___% ± ___%

Answer 1

`p \± ME`
`\to`
`71.2\% \± 7.9\%`

Explanation:

Given

`(63.3\%,79.1\%)`

Required

Express in form of:
`p \± ME`

First, calculate the midpiont (p)

`p = (63.3\% + 79.1\%)/(2)`

`p = (142.4\%)/(2)`

`p = 71.2\%`

The margin of error (ME) is:

`ME =79.1\% - 71.2\%`

`ME =7.9\%`

So, we have:

`p \± ME`
`\to`
`71.2\% \± 7.9\%`