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PLEASE HELP!!

Find the equation of the axis of symmetry of the parabola. Each box in the grid represents 1 unit.


Enter the answer as an equation.

PLEASE HELP!! Find the equation of the axis of symmetry of the parabola. Each box-example-1

2 Answers

6 votes

Answer:

2

Explanation:

User Mauzzam
by
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13 votes

Answer:

The axis of symmetry of this parabola will be the line x=−b2a .

Explanation:

Graph the parabola y=x2−7x+2 .

Compare the equation with y=ax2+bx+c to find the values of a , b , and c .

Here, a=1,b=−7 and c=2 .

Use the values of the coefficients to write the equation of axis of symmetry .

The graph of a quadratic equation in the form y=ax2+bx+c has as its axis of symmetry the line x=−b2a . So, the equation of the axis of symmetry of the given parabola is x=−(−7)2(1) or x=72 .

Substitute x=72 in the equation to find the y -coordinate of the vertex.

y=(72)2−7(72)+2 =494−492+2 =49 − 98 + 84  =−414

Therefore, the coordinates of the vertex are (72,−414) .

User Kalem
by
8.9k points

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