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A furniture designer builds a trapezoidal desk with a semicircular cutout. What is the area of the desk?

User ATD
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1 Answer

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Answer:


Area = 26478cm^2

Explanation:

Given

See attachment for desk

Required

The area

First, calculate the area of the semicircular cutout


Area = (\pi r^2)/(2)

Where


r = 60cm

So:


A_1 = (3.14 * 60^2)/(2)


A_1 = (11304)/(2)


A_1 = 5652cm^2

Next, the area of the complete trapezium


Area= (1)/(2)(a + b) * h

Where


a = 300


b = 2 * r = 2 * 60 = 120


h = 153

So:


A_2 = (1)/(2) * (300 + 120) * 153


A_2 = (1)/(2) * 420 * 153


A_2 = 32130cm^2

The area of the desk is:


Area = A_2 - A_1


Area = 32130cm^2 - 5652cm^2


Area = 26478cm^2

A furniture designer builds a trapezoidal desk with a semicircular cutout. What is-example-1
User Nababa
by
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