Question

How many liters are 1.20 g of oxygen?

Answer 1

The required volume is 0.84 L

Step-by-step explanation:

Given,

Mass of O2 gas = 1.20 g

We know,

At STP, molar volume of all gases is 22.4 L

and Molar mass of O2 gas is 32 g

Now,

Number of moles = mass/molar mass

= 1.20/32

= 0.0375

Again,

At STP,

Number of moles = Volume/Molar volume

or, Volume = Number of moles X Molar Volume

or Volume = 0.0375 X 22.4

∴ Volume = 0.84 L

So, the required volume is 0.84 L