Answer:
the sound intensity level for actual intensity ( without the earplugs ) is 103.8 dB
Step-by-step explanation:
Given the data in the question;
sound intensity reduced by the factor, m = 305
the sound intensity level experienced by the crew members wearing protective earplugs, L = 79 dB
Now, using the expression of sound intensity level;
L = 10log(
)
where
is the intensity at L level
so we substitute
79 = 10log(
)
=
Now, expression for actual intensity;
= m
where
is the actual intensity
so we substitute
= 305 ×
Next, we write the expression of sound intensity level for reduced intensity;
L' = 10log(
)
So we substitute
L' = 10log( 305 ×
)
L' = 10log( 24227011159.09058 )
L' = 103.8 dB
Therefore, the sound intensity level for actual intensity ( without the earplugs ) is 103.8 dB