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point a is at (-7 5) and point c is at (5 -1). find the coordinates of point b on line ab such that ab is 5 times as long as bc

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Explanation:

Let the coordinates of point b be (x,y).

Given the coordinates of a (-7,5) and c(5,-1)

Now according to question

ab = 5bc

using distance formula


√((x+7)^2+(y-5)^2) =5√((5-x)^2+(-1-y)^2)

Solving we can get


x=-(-11+√(-4y^2-10y+25))/(2),\:x=(√(-4y^2-10y+25)+11)/(2)'

However, we do need either x or y coordinate of point b to find the other.

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