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Solve 2x^2
+ x - 4= 0.
x2 +
= 0
DONE

1 Answer

4 votes


\\ \sf\longmapsto 2x^2+x-4=0


\\ \sf\longmapsto 2x^2+x=4


\\ \sf\longmapsto 8(2x^2+x=4)


\\ \sf\longmapsto 16x^2+8x=32


\\ \sf\longmapsto (4x)^2+2(4x)(1)=32


\\ \sf\longmapsto 4x^2+2(4x)(1)+1^2=32+1^2


\\ \sf\longmapsto (4x+1)^2=33


\\ \sf\longmapsto 4x+1=\pm√(33)


\\ \sf\longmapsto 4x=-1\pm√(33)


\\ \sf\longmapsto x=(-1\pm√(33))/(4)

User Rick Roberts
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