Final answer:
The concentration of the HNO3(aq) solution can be calculated by using the volume and concentration of NaOH solution to find the moles of NaOH, which are equal to the moles of HNO3 due to the 1:1 stoichiometry of the reaction. The concentration of HNO3 is then found by dividing the moles of HNO3 by the volume of HNO3 in liters.
Step-by-step explanation:
To calculate the concentration of the HNO3(aq) solution, you can set up the calculation based on the neutralization reaction between HNO3 and NaOH. The balanced chemical equation for this reaction is HNO3(aq) + NaOH(aq) → NaNO3(aq) + H2O(l). Since the stoichiometry between the acid and the base is 1:1, we can use the volume and the molarity of NaOH to find the moles of NaOH, which will be equal to the moles of HNO3 due to the 1:1 ratio.
The correct numerical setup for calculating the concentration of the HNO3(aq) solution is:
(Volume of NaOH) × (Molarity of NaOH) = Moles of NaOH = Moles of HNO3
(Concentration of HNO3) = (Moles of HNO3) / (Volume of HNO3)
In this case, it would look like:
0.030 L × 0.15 M = x moles of HNO3
x moles of HNO3 / 0.035 L = Concentration of HNO3
By solving for the moles of HNO3 and dividing by the volume of HNO3 in liters, you will find the concentration in molarity (M) of the HNO3 solution.