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If a fisherman applies a horizontal force with magnitude 47.0 NN to the box and produces an acceleration of magnitude 3.20 m/s2m/s2, what is the mass of the box

1 Answer

3 votes

Answer:

The correct solution is "14.6875 kg".

Step-by-step explanation:

Given values:

Force,

F = 47.0 N

Acceleration,

a = 3.20 m/s²

Now,


Force=Mass* Acceleration

or,


F=ma


47.0=m* 3.20


m=(47.0)/(3.20)


=14.6875 \ kg

User Shomeax
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