256 views
0 votes
A. What is the change in internal energy for each of the following situations? q = 7.9 J out of the system and w = 3.6 J done on the system q = 1.5 J into the system and w = 7.5 J done on the system

User Itsatony
by
5.2k points

1 Answer

6 votes

Answer:
-4.3\ J,\ 9\ J

Step-by-step explanation:

Given

(a)

Heat transfer
Q=-7.9\ J\quad \text{taken}

Work done
W=-3.6\ J\quad \text{on the system}

Change in the internal kinetic energy is


\Delta U=Q-W\\\Rightarrow \Delta U=-7.9-(-3.6)\\\Rightarrow \Delta U=-4.3\ J

(b)

Heat transfer
Q=1.5\ J\quad \text{given}

Work done
W=-7.5\ J\quad \text{on the system}

Change in the internal kinetic energy is


\Delta U=Q-W\\\Rightarrow \Delta U=1.5-(-7.5)\\\Rightarrow \Delta U=9\ J

User Puppybits
by
5.6k points