Question

If you shine a light of frequency 375hz on a double slit setup , and you measure the slit separation to be 950 nm and the screen distance to be 4030 nm away , what is the distance from the zero order fringe to the first order fringe ?

Answer 1

y = 33.93 10⁵ m

Step-by-step explanation:

This is an interference exercise, for the contributory interference is described by the expression

d sin θ = m λ

let's use trigonometry for the angle

tan θ = y / L

how the angles are small

tan θ = sin θ / cos tea = sin θ

we substitute

sin θ = y / L

d y / L = m λ

y = m λ L / d

the light fulfills the relation of the waves

c = λ f

λ = c / f

λ = 3 10⁸ /375

λ = 8 10⁵ m

first order m = 1

let's calculate

y = 1 8 10⁵ 4030 10-9 / 950 10-9

y = 33.93 10⁵ m