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Given the vertices of a triangle ABC below, find the midpoint and length of the midsegment. Give your length in simplified radical form.

Given the vertices of a triangle ABC below, find the midpoint and length of the midsegment-example-1
User Grimm
by
8.0k points

1 Answer

1 vote

Answer:

Midpoint of AC = (-1, 1)

Midpoint of BC = (1, -2)

Length of the midsegment =
√(13)

Explanation:

Vertices of a triangle ABC are A(0, 5), B(4, -1) and C(-2, -3).

Midpoint of segment AC =
(x_1+x_2)/(2),(y_1+y_2)/(2)

=
((0-2)/(2),(5-3)/(2))

= (-1, 1)

Midpoint of BC =
((4-2)/(2),(-1-3)/(2))

=
(1,-2)

Length of the mid segment =
√((x_2-x_1)^2+(y_2-y_1)^2)

=
√((-1-1)^2+(-2-1)^2)

=
√(4+9)

=
√(13)

User Will Ness
by
8.0k points

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