Question

Find the equation of the linear relationship.

Answer 1

y = -3x + 150

Explanation:

2 points on the graph:

(30, 60) and (40, 30)

Slope:

m=(y2-y1)/(x2-x1)

m=(30 - 60)/(40 - 30)

m= (-30)/10

m= -3

Slope-intercept:

y - y1 = m(x - x1)

y - 60 = -3(x - 30)

y - 60 = -3x + 90

y = -3x + 150