Register
If 143.56 mL of 0.6653 M ammonium carbonate reacts with 175.37 mL of 0.8732 M chromium(III) sulfate in a double replacement reaction and produces 7.543 g of chromium(III) carbonate, what is the percent
15.9k views
2 votes
If 143.56 mL of 0.6653 M ammonium carbonate reacts with 175.37 mL of 0.8732 M chromium(III) sulfate in a double replacement reaction and produces 7.543 g of chromium(III) carbonate, what is the percent yield of the reaction

User Anduin
by
2.9k points

2 Answers

2 votes
I think it’s 7543 g of chromium
User Mirage
by
3.5k points
3 votes
ANSWER=83.42%

Step-by-step explanation:
If 143.56 mL of 0.6653 M ammonium carbonate reacts with 175.37 mL of 0.8732 M chromium-example-1
User Christian Navelot
by
3.3k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

3.3m questions

4.2m answers

Other Questions

What is the variable for this number 22.4L?
A helium balloon containing 0.100 mol of gas occupies a volume of 2.4 L at 25 C and 1.0 atm. how many moles have we added if we inflate it to 5.6 L?
TRUE or FALSE: Volcanoes help warm the planet by releasing CO2 (carbon dioxide)
Which of the following is NOT a benefit of wildfires? * O Insects moving in after a fire provide more food for birds. O Wildfires help undergrowth in a forest grow denser. O Fires can clean out diseased
Calculate the number of moles of sodium hydroxide in 8g of sodium hydroxide (NaOH). Na=23 O=16 H=1
Link Copied!