Answer:
![\mu_(max)=200Mpa](https://img.qammunity.org/2022/formulas/engineering/college/69kufmjctyzny4tey5qhknmhg0k7gifq55.png)
Step-by-step explanation:
From the question we are told that:
Internally pressurized
![P_i=100MPa](https://img.qammunity.org/2022/formulas/engineering/college/fd6afq79jt5kdpayc1p7b20lv3xjt44aw2.png)
Tangential Stress
![P_t=400mpa](https://img.qammunity.org/2022/formulas/engineering/college/jjrcrkbduflwkyev2fd7u5cu6635m5qiax.png)
Axial stress
![P_a=200mpa](https://img.qammunity.org/2022/formulas/engineering/college/sfa85zyq8fgjj6daszvudcqjeu4myuu9vc.png)
Generally the equation for maximum normal and shear stresses are experienced by the outer surface is mathematically given by
![\mu_(max)=|(P_t-P_a)/(2)|,|(P_t)/(2)|,|(P_t)/(2)|](https://img.qammunity.org/2022/formulas/engineering/college/teg7hbgdmoo06ylibq59hjjtu6uc7g9itc.png)
Therefore
![\mu_(max)=|(400-200)/(2)|,|(400)/(2)|,|(200)/(2)|](https://img.qammunity.org/2022/formulas/engineering/college/lbik4bjpzyhpv2lni2drr82iynys9d56ok.png)
![\mu_(max)=200Mpa](https://img.qammunity.org/2022/formulas/engineering/college/69kufmjctyzny4tey5qhknmhg0k7gifq55.png)