Question

What is the molarity of a solution that is composed of 10 grams of Sodium Chloride ( NaCl) dissolved in 3.50 L of water

Answer 1

Answer: The molarity of solution will be 0.049 M

Step-by-step explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

`\text{Molarity of solution}=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}* \text{Volume of solution (L)}}`

We are given:

Given mass of sodium chloride = 10 g

Molar mass of sodium chloride = 58.44 g/mol

Volume of solution = 3.50 L

Putting values in above equation:

`\text{Molarity of NaCl}=(10 g)/(58.44g/mol* 3.50)\\\\\text{Molarity of NaCl}=0.049M`

Hence, the molarity of solution will be 0.049 M